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# std::remquo

From cppreference.com
< cpp‎ | numeric‎ | math

Defined in header `<cmath>` |  |
float remquo( float x, float y, int* quo ); | (1) | (since C++11)
double remquo( double x, double y, int* quo ); | (2) | (since C++11)
long double remquo( long double x, long double y, int* quo ); | (3) | (since C++11)
Promoted remquo( Arithmetic1 x, Arithmetic2 y, int* quo ); | (4) | (since C++11)

1-3) Computes the floating-point remainder of the division operation x/y as the std::remainder() function does. Additionally, the sign and at least the three of the last bits of x/y will be stored in quo, sufficient to determine the octant of the result within a period.
4) A set of overloads or a function template for all combinations of arguments of arithmetic type not covered by 1-3. If any non-pointer argument has integral type, it is cast to double. If any other non-pointer argument is long double, then the return type is long double, otherwise it is double.

### [edit] Parameters

x, y | - | floating point values
quo | - | pointer to an integer value to store the sign and some bits of x/y

### [edit] Return value

If successful, returns the floating-point remainder of the division x/y as defined in std::remainder, and a value whose sign is the sign of x/y and whose magnitude is congruent modulo 2n
to the magnitude of the integral quotient of x/y, where n is an implementation-defined integer greater than or equal to 3.

If `y` is zero, the value stored in *quo is unspecified.

If a domain error occurs, an implementation-defined value is returned (NaN where supported)

If a range error occurs due to underflow, the correct result is returned if subnormals are supported.

If `y` is zero, but the domain error does not occur, zero is returned.

### [edit] Error handling

Errors are reported as specified in math_errhandling

Domain error may occur if `y` is zero.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

- The current rounding mode has no effect.
- FE_INEXACT is never raised
- If `x` is ±∞ and `y` is not NaN, NaN is returned and FE_INVALID is raised
- If `y` is ±0 and `x` is not NaN, NaN is returned and FE_INVALID is raised
- If either `x` or `y` is NaN, NaN is returned

### [edit] Notes

POSIX requires that a domain error occurs if `x` is infinite or `y` is zero.

This function is useful when implementing periodic functions with the period exactly representable as a floating-point value: when calculating sin(πx) for a very large `x`, calling std::sin directly may result in a large error, but if the function argument is first reduced with `std::remquo`, the low-order bits of the quotient may be used to determine the sign and the octant of the result within the period, while the remainder may be used to calculate the value with high precision.

On some platforms this operation is supported by hardware (and, for example, on Intel CPUs, `FPREM1` leaves exactly 3 bits of precision in the quotient when complete).

### [edit] Example

Run this code

    #include <iostream>
    #include <cmath>
    #include <cfenv>

    #pragma STDC FENV_ACCESS ON
    const double pi = std::acos(-1);
    double cos_pi_x_naive(double x) { return std::cos(pi * x); }
    // the period is 2, values are (0;0.5) positive, (0.5;1.5) negative, (1.5,2) positive
    double cos_pi_x_smart(double x)
    {
        int quadrant;
        double rem = std::remquo(x, 1, &quadrant);
        quadrant = (unsigned)quadrant % 4; // keep 2 bits to determine quadrant
        switch(quadrant) {
            case 0: return std::cos(pi * rem);
            case 1: return -std::cos(pi * rem);
            case 2: return -std::cos(pi * rem);
            case 3: return std::cos(pi * rem);
        };
    }
    int main()
    {
        std::cout << "cos(pi * 0.25) = " << cos_pi_x_naive(0.25) << '\n'
                  << "cos(pi * 1.25) = " << cos_pi_x_naive(1.25) << '\n'
                  << "cos(pi * 1000000000000.25) = "
                  << cos_pi_x_naive(1000000000000.25) << '\n'
                  << "cos(pi * 1000000000001.25) = "
                  << cos_pi_x_naive(1000000000001.25) << '\n'
                  << "cos(pi * 1000000000000.25) = "
                  << cos_pi_x_smart(1000000000000.25) << '\n'
                  << "cos(pi * 1000000000001.25) = "
                  << cos_pi_x_smart(1000000000001.25) << '\n';
        // error handling
        std::feclearexcept(FE_ALL_EXCEPT);
        int quo;
        std::cout << "remquo(+Inf, 1) = " << std::remquo(INFINITY, 1, &quo) << '\n';
        if(fetestexcept(FE_INVALID)) std::cout << "    FE_INVALID raised\n";
    }

Possible output:

    cos(pi * 0.25) = 0.707107
    cos(pi * 1.25) = -0.707107
    cos(pi * 1000000000000.25) = 0.707123
    cos(pi * 1000000000001.25) = -0.707117
    cos(pi * 1000000000000.25) = 0.707107
    cos(pi * 1000000000001.25) = -0.707107
    remquo(+Inf, 1) = -nan
        FE_INVALID raised

### [edit] See also

div(int)ldivlldiv (C++11) | computes quotient and remainder of integer division (function) [edit]
fmod | remainder of the floating point division operation (function) [edit]
remainder (C++11) | signed remainder of the division operation (function) [edit]
C documentation for remquo

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