log10, log10f, log10l - cppreference.com

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# log10, log10f, log10l

From cppreference.com
< c‎ | numeric‎ | math

Defined in header `<math.h>` |  |
float log10f( float arg ); | (1) | (since C99)
double log10( double arg ); | (2) |
long double log10l( long double arg ); | (3) | (since C99)
Defined in header `<tgmath.h>` |  |
#define log10( arg ) | (4) | (since C99)

1-3) Computes the common (base-10) logarithm of `arg`.
4) Type-generic macro: If `arg` has type long double, `log10l` is called. Otherwise, if `arg` has integer type or the type double, `log10` is called. Otherwise, `log10f` is called.

### [edit] Parameters

arg | - | floating point value

### [edit] Return value

If no errors occur, the common (base-10) logarithm of `arg` (log
10(arg) or lg(arg)) is returned.

If a domain error occurs, an implementation-defined value is returned (NaN where supported)

If a pole error occurs, `-HUGE_VAL`, `-HUGE_VALF`, or `-HUGE_VALL` is returned.

### [edit] Error handling

Errors are reported as specified in math_errhandling

Domain error occurs if `arg` is less than zero.

Pole error may occur if `arg` is zero.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

- If the argument is ±0, -∞ is returned and FE_DIVBYZERO is raised.
- If the argument is 1, +0 is returned
- If the argument is negative, NaN is returned and FE_INVALID is raised.
- If the argument is +∞, +∞ is returned
- If the argument is NaN, NaN is returned

### [edit] Example

Run this code

    #include <stdio.h>
    #include <math.h>
    #include <float.h>
    #include <errno.h>
    #include <fenv.h>
    #pragma STDC FENV_ACCESS ON
    int main(void)
    {
        printf("log10(1000) = %f\n", log10(1000));
        printf("log10(0.001) = %f\n", log10(0.001));
        printf("base-5 logarithm of 125 = %f\n", log10(125)/log10(5));
        // special values
        printf("log10(1) = %f\n", log10(1));
        printf("log10(+Inf) = %f\n", log10(INFINITY));
        //error handling
        errno = 0; feclearexcept(FE_ALL_EXCEPT);
        printf("log10(0) = %f\n", log10(0));
        if(errno == ERANGE) perror("    errno == ERANGE");
        if(fetestexcept(FE_DIVBYZERO)) puts("    FE_DIVBYZERO raised");
    }

Possible output:

    log10(1000) = 3.000000
    log10(0.001) = -3.000000
    base-5 logarithm of 125 = 3.000000
    log10(1) = 0.000000
    log10(+Inf) = inf
    log10(0) = -inf
        errno == ERANGE: Numerical result out of range
        FE_DIVBYZERO raised

### [edit] See also

loglogflogl (C99)(C99) | computes natural (base-e) logarithm (ln(x)) (function) [edit]
log2log2flog2l (C99)(C99)(C99) | computes base-2 logarithm (log2(x)) (function) [edit]
log1plog1pflog1pl (C99)(C99)(C99) | computes natural (base-e) logarithm of 1 plus the given number (ln(1+x)) (function) [edit]
C++ documentation for log10

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